Trouble converting hex to decimal?

[Adam DePrince]

On Sat, 2005-02-05 at 12:02, Steve Holden wrote:
> Pedro Werneck wrote:
> > The problem is that '\x00' is a escape sequence... 
> > Try something like this:
> >>>>x = '\x00'
> >>>>int(repr(x)[3:-1], 16)
> > 0
> >>>>x = '\x15'
> >>>>int(repr(x)[3:-1], 16)
> > 21
> > On Sat, 05 Feb 2005 06:51:32 -0700
> > Earl Eiland <eee at nmt.edu> wrote:
> >>I'm trying to process the IP packet length field, as recorded by pcap
> >>(Ethereal) and recovered using pcapy.  When I slice out those bytes, I
> >>get a value that shows in '\x00' format, rather than '0x00'.  Neither
> >>int() nor eval() are working.  How do I handle this?
> >>Earl Eiland
> Talk about making things difficult!
>   >>> x = '\x00'
>   >>> ord(x)
> 0
>   >>> x = '\x15'
>   >>> ord(x)
> 21
>   >>>

Ethereal's emission of \x00 shouldn't make your life any more
difficult.  The conversion of \0xx takes place in the eval.  If you
store the string \x00 in a file and call open.read or command.getoutput,
you will get the python string "\\x00".  Stuff you read from a file
arrives un-de-escaped.

The solution is simple.  

mystring.replace( "\x","0x" )




Adam DePrince