changing __call__ on demand

[Alan McIntyre]

I tried this:

 >>>class test(object):
...	def __call1(self):
...		print 1
...	__call__ = __call1
...
 >>>t = test()
 >>>t()
1
 >>>

Is that what you were looking for?

-- 
Alan McIntyre
ESRG LLC
http://www.esrgtech.com

Stefan Behnel wrote:
> Hi!
> 
> This somewhat puzzles me:
> 
> Python 2.4 (#1, Feb  3 2005, 16:47:05)
> [GCC 3.3.4 (pre 3.3.5 20040809)] on linux2
> Type "help", "copyright", "credits" or "license" for more information.
> 
> .>>> class test(object):
> ...   def __init__(self):
> ...     self.__call__ = self.__call1
> ...   def __call1(self):
> ...     print 1
> ...   def __call__(self):
> ...     print 2
> ...
> .>>> t = test()
> .>>> t()
> 2
> 
> If I take out the __call__ method completely and only set it in 
> __init__, I get a TypeError saying that test is not callable.
> 
> I want to use this in order to provide different implementations based 
> on the object configuration. Calculating the right function to call is 
> non-trivial and calls are frequent, so I want to change __call__ in 
> order to run the right function directly.
> 
> I know, I could use another level of indirection:
> 
> def __call__(self):
>   self.the_right_method()
> 
> and then set the_right_method accordingly, but I find that somewhat 
> sub-optimal. Is there a way to change __call__ after class creation?
> 
> Stefan