i=2; lst=[i**=2 while i<1000]
Daniel Schüle
uval at rz.uni-karlsruhe.de
Tue Dec 6 09:17:27 EST 2005
D H wrote:
> bonono at gmail.com wrote:
>
>>> You can use i**=2 for i in range(1000) instead
>>
>>
>>
>> I don't think one can use assignment in list comprehension or generator
>> expression. The limitation is very much like lambda.
>>
>
> i**2
lst=[i**2 for i in range(1000)]
you will get a list with 1000 items
[0,1,4,9 ... ]
is not the same as
i,lst=2,[]
while i<1000:
i**=2
lst.append(i)
here you get [4,16,256,65536]
only 4 items
Regards, Daniel
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