Easiest way to calculate number of character in string

[Carsten Haese]

On Wed, 2005-12-21 at 09:03, P. Schmidt-Volkmar wrote:
> Hi there,
> 
> I have a string in which I want to calculate how often the character  ';' 
> occurs. If the character does not occur 42 times, the ";" should be added so 
> the 42 are reached.
> 
> My solution is slow and wrong:
>     for Position in range (0, len(Zeile)):
>         if Zeile[Position]==';': AnzahlSemikolon = AnzahlSemikolon +1
>     if AnzahlSemikolon < 42:
>         for Zaehler in range(AnzahlSemikolon, 42):
>             Zeile = Zeile + ';'
>         Dreckskram = Dreckskram +1
> 
> How can this be achieved easily?
> 
> Thanks,
> 
> Pascal

AnzahlSemikolon = Zeile.count(';')
if AnzahlSemikolon < 42:
    Zeile += ';'*(42-AnzahlSemikolon)

HTH,

Carsten.