Using XML w/ Python...

[uche.ogbuji at gmail.com]

"""
 Ok, i am now understanding some of parseing and how to use it and
nodes, things like that. But say i wanted to take the title of
http://www.digg.com/rss/index.xml

and XMLTramp seemed the most simple to understand.

would the path be something like this?

import xmltramp
rssDigg = xmltramp.load("http://www.digg.com/rss/index.xml")
print note.rss.channel.item.title

I think thats wat im having the most confusion on now, is how to direct
to the path that i want...
"""

I suggest you read at least the front page information for the tools
you are using.  It's quite clear from the xmltramp Web site (
http://www.aaronsw.com/2002/xmltramp/ ) that you want tomething like
(untested: the least homework you can do is to refine the example
yourself):

print rssDigg[rss.channel][item][title]

BTW, in Amara, the API is pretty much exactly what you guessed:

>>> import amara
>>> rssDigg = amara.parse("http://www.digg.com/rss/index.xml")
>>> print rssDigg.rss.channel.item.title
Video: Conan O'Brien iPod Ad Parody


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Uche Ogbuji                               Fourthought, Inc.
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