Does any one recognize this binary data storage format

[Roel Schroeven]

Dejan Rodiger wrote:
> geskerrett at hotmail.com said the following on 9.08.2005 19:29:
> 
>>Phone 1: 5616864700
>>Hex On Disk: C0DBA8ECF441
> 
> 
> 5616864700(10)=14ECA8DBC(16)
> 14 EC A8 DB C    leftshift by 4 bits (it will add 0 on last C)
> C0 DB A8 EC 14 00 write bytes from right to left
> C0 DB A8 EC F4 41 Add E041
> 
> 
>>Phone 1: 8003346488
>>Hex On Disk: 800396d0fd41
> 
> 
> 8003346488(10)=1DD096038(16)
> 1D D0 96 03 8
> 80 03 96 D0 1D 00
> 80 03 96 d0 fd 41 Add E041
> 
> But works only for Phone 1 :-)

E041 is some kind of checksum perhaps?

-- 
If I have been able to see further, it was only because I stood
on the shoulders of giants.  -- Isaac Newton

Roel Schroeven