Really virtual properties
Diez B. Roggisch
deets at web.de
Thu Aug 18 17:44:44 EDT 2005
I don't think so - the reason is that property(<getter>) is evaluated
in the baseclass, and stores a callable, not a name. the only thing you
could do is either
- create a level of indirection, using lambda, to force the lookup:
x = property(lamda self: self.get_x())
- use a metaclass, that tries to scan the baseclass for properties
that uise functionnames which are redefined in the current class, and
recrerate a new property for those.
Diez
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