aproximate a number

[Will McGugan]

billiejoex wrote:
> Hi all. I'd need to aproximate a given float number into the next (int) 
> bigger one. Because of my bad english I try to explain it with some example:
> 
> 5.7 --> 6
> 52.987 --> 53
> 3.34 --> 4
> 2.1 --> 3
> 

Have a look at math.ceil

 >>> import math
 >>> math.ceil(5.7)
6.0


Will McGugan
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