Dictionary question.

bserviss bserviss at triad.rr.com
Fri Apr 22 22:02:33 EDT 2005


A simple way to get individual values for the distribution is:

d = {}
for i in range( 0, 1000):
    j = random.randrange( 0, 100)
    if d.has_key(j):
        d[j] += 1
    else:
         d[j] = 1

keys = d.keys()
keys.sort()
for key in keys:
    print key, ":", "*" * d[key]




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