ATTN : Georges ( gry at ll.mit.edu)

m_tach at yahoo.com m_tach at yahoo.com
Tue Apr 12 14:16:22 EDT 2005


First of all thanks for helping me out.

I have to admit I dont understand some of your suggestiosn, sorry.
I dont know what is the "3D" thing... Is there another way to make it
work something more simple for a newbie like me? Thanks

What I want to do is:
First check all the files from a folder and analyze only the one with the .Seq extension.
What I want to do is to get the reverse complement of the DNA sequence. If their is a problem
with some characters in the DNA Sequence I want the function to tell it to me.

Here are the comp and iupac:

iupac ="GgAaTtCcRrYyMmKkSsWwHhBbVvDdNn"

comp={"A":"T", "T":"A", "G":"C", "C":"G", "R":"Y", "Y":"R", "M":"K",
"K":"M", "S":"W", "W":"S", "B":"V", "V":"B", "D":"H", "H":"D", "r":"y",
"y":"r", "m":"k", "k":"m", "s":"w", "w":"s", "b":"v", "v":"b", "d":"h",
"h":"d", "a":"t", "t":"a", "g":"c", "c":"g", "N":"N","n":"n"}

So if a $ or Z appears in the DNA sequence, I want to know it. 

My code so far:
# -*- coding: iso-8859-1 -*-
import sys
import os
from progadn import *

ab1seq = raw_input("Entrez le répertoire où sont les fichiers à analyser: ") or None
if ab1seq == None :
    print "Erreur: Pas de répertoire! \n" \
"\nAu revoir \n"
    sys.exit()

listrep = os.listdir(ab1seq)
#print listrep

extseq=[]

for f in listrep:
     if f[-4:]==".Seq":
         extseq.append(f)
         #print extseq

for x in extseq:
     f=open(x, "r")
     seq=f.read()
     f.close()
     #s=seq


def checkDNA(seq):
    """Retourne une liste des caractères non conformes à l'IUPAC."""

    junk=[]
    for c in range (len(seq)):
        if seq[c] not in iupac:
            junk.append([seq[c],c])
            #print junk
            print "ATTN: Il y a le caractère %s en position %s " % (seq[c],c)
        if junk == []:
             indinv=range(len(seq))
             indinv.reverse()
             resultat=""
             for i in indinv:
                 resultat +=comp[seq[i]]
             return resultat

seq=checkDNA(seq)

-------------------------------------------------------------------------------------------------------------------------

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From: gry at ll.mit.edu
Newsgroups: comp.lang.python
Subject: Re: problem with the logic of read files
Date: 12 Apr 2005 10:47:17 -0700
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<m_t... at yahoo.com> wrote:
> I am new to python and I am not in computer science. In fact I am a
biologist and I ma trying to learn python. So if someone can help me, I
will appreciate it.
> Thanks
>
>
> #!/cbi/prg/python/current/bin/python
> # -*- coding: iso-8859-1 -*-
> import sys
> import os
> from progadn import *
>
> ab1seq =3D raw_input("Entrez le r=E9pertoire o=F9 sont les fichiers =E0
analyser: ") or None
> if ab1seq =3D=3D None :
>     print "Erreur: Pas de r=E9pertoire! \n"
> "\nAu revoir \n"
>     sys.exit()
>
> listrep =3D os.listdir(ab1seq)
> #print listrep
>
> extseq=3D[]
>
> for f in listrep:
###### Minor -- this is better said as:  if f.endswith(".Seq"):
>      if f[-4:]=3D=3D".Seq":
>          extseq.append(f)
> #         print extseq
>
> for x in extseq:
>      f =3D open(x, "r")
###### seq=3D... discards previous data and refers only to that just
read.
###### It would be simplest to process each file as it is read:
@@@@@@ seq=3Df.read()
@@@@@@ checkDNA(seq)
>      seq=3Df.read()
>      f.close()
>      s=3Dseq
>
> def checkDNA(seq):
>     """Retourne une liste des caract=E8res non conformes =E0
l'IUPAC."""
>
>     junk=3D[]
>     for c in range (len(seq)):
>         if seq[c] not in iupac:
>             junk.append([seq[c],c])
>             #print junk
>             print "ATTN: Il y a le caract=E8re %s en position %s " %
(seq[c],c)
>         if junk =3D=3D []:
>              indinv=3Drange(len(seq))
>              indinv.reverse()
>              resultat=3D""
>              for i in indinv:
>                  resultat +=3Dcomp[seq[i]]
>              return resultat
>
> seq=3DcheckDNA(seq)
> print seq

##### The program segment you posted did not define "comp" or "iupac",
##### so it's a little hard to guess how it's supposed to work.  It
would
##### be helpful if you gave a concise description of what you want the

##### program to do, as well as brief sample of input data.
##### I hope this helps!  -- George
>
> #I got the following ( as you see only one file is proceed by the
function even if more files is in extseq
>
> ['B1-11_win3F_B04_04.ab1.Seq']
> ['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq']
> ['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-18_win3F_D04_08.ab1.Seq']
> ['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq']
> ['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq',
'B1-19_win3F_F04_12.ab1.Seq']
> ..
> ['B1-11_win3F_B04_04.ab1.Seq', 'B1-11_win3R_C04_06.ab1.Seq',
'B1-18_win3F_D04_08.ab1.Seq', 'B1-18_win3R_E04_10.ab1.Seq',
'B1-19_win3F_F04_12.ab1.Seq', 'B1-19_win3R_G04_14.ab1.Seq',
'B90_win3F_H04_16.ab1.Seq', 'B90_win3R_A05_01.ab1.Seq',
'DL2-11_win3F_H03_15.ab1.Seq', 'DL2-11_win3R_A04_02.ab1.Seq',
'DL2-12_win3F_F03_11.ab1.Seq', 'DL2-12_win3R_G03_13.ab1.Seq',
'M7757_win3F_B05_03.ab1.Seq', 'M7757_win3R_C05_05.ab1.Seq',
'M7759_win3F_D05_07.ab1.Seq', 'M7759_win3R_E05_09.ab1.Seq',
'TCR700-114_win3F_H05_15.ab1.Seq', 'TCR700-114_win3R_A06_02.ab1.Seq',
'TRC666-100_win3F_F05_11.ab1.Seq', 'TRC666-100_win3R_G05_13.ab1.Seq']
>
> after this listing my programs proceed only the last element of this
listing (TRC666-100_win3R_G05_13.ab1.Seq)
>
>
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCAAAACGTTTTTAG=
NNNNNNNNNNNNNNNNNNNNNNNNNNNNNNTCCCGAAGTGTCCCAGAGCAAATAAATGGACCAAAACGTTTTTAG=
AATACTTGAACGTGTAATCTCATTTTAA



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