preallocate list
Mike C. Fletcher
mcfletch at rogers.com
Wed Apr 13 09:46:22 EDT 2005
Jim wrote:
> Thanks for the suggestions. I guess I must ensure that this is my
> bottle neck.
...
> for line in f:
> factor = []
> tokens = line.split()
> for i in tokens:
> factor.append(float(i))
> factors.append(loadFactor)
>
...
You might try:
factors = [ [float(item) for item in line.split()] for line in f ]
avoiding the extra statements for appending to the lists. Also might try:
factors = [ map(float, line.split()) for line in f ]
though it uses the out-of-favour functional form for the mapping.
Good luck,
Mike
________________________________________________
Mike C. Fletcher
Designer, VR Plumber, Coder
http://www.vrplumber.com
http://blog.vrplumber.com
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