Compute pi to base 12 using Python?

Wed Apr 13 06:19:31 EDT 2005

On Wed, 13 Apr 2005 02:06:11 -0700, Dick Moores <rdm at rcblue.com> wrote:

>I need to figure out how to compute pi to base 12, to as many digits as 
>possible. I found this reference, 
><http://mathworld.wolfram.com/Base.html>, but I really don't understand 
>it well enough. Could someone show me how to do what I need?
>
>Thanks,
>
>Dick Moores
>rdm at rcblue.com
>
See if this is enough digits for homework? ;-) 

(Digits A and B are 10 and 11 in decimal respectively)

3184809493B918664573A6211BB151551A05729290A7809A492742140A60A55256A0661A03753A3AA54805646880181A
3683083272BBBA0A370B12265529A828903B4B256B8403759A71626B8A54687621849B849A8225616B442796A31737B2
29B2391489853943B8763725616447236B027A421AA17A38B52A18A838B01514A51144A23315A3009A8906B61B8B48A6
2253A88A50A43BA0944572315933664476B3AABB77583975120683526B75B462060BB03B432551913772729A21475535
31793848A0402B999B5058535374465A68806716644039539A8431935198527B9399B112990ABB0383B107645424577A
51601B3624A88B7A676A3992912121A213887B92873946A61332242217AA7354115357744939112602BA4B888818A326
9222B528487747839994AB223B65B8762695422822669BA00A586097842A51750362073B5A768363B21BB1A97A4A1944
47749399804922175A068A46739461990A2065BB0A30BBAB7024A585B1A84428195489784A07A331A7B0A1574565B373
B05B03A5A80A13AB87857734679985558A5373178A7B28271992A3894A5776085083B9B238B2220542462888641A2BAB
8B3083AB49659172A312B78518654494A068662586A181835A64440B2970A12281397589881536720890580103288144
9223841428763329617531239B9A657405584014534390B587625606BB80923795944B43757A431B039556282978A6A4
9590553490BA1844947175637A908247B50127722464441380A852B0847B5813019BB70A67663B426565434069884476
132193344BA55A2128A03838974606B851B2979321A408067225A5AA4B3464A1A17473595333909AB9127079655B3164
B68B9B28A9B818A220A025AB0934203995B7A62A7AA739355340539BA3182905B193905603A43B660B9426A922946971
44A896A5B2339358BB2B7294BB89635B071A6351211360B820B1882AB8433B54757B87A373284B1BA182A10326476B36
9A4A6365B58B8018994BB152556765475A704BB94B6B2A39458971A8B90512786B5029404818644323552916170B3ABB
7363496427B088B68725A68570040617949289077B278069A09B559324B8A66828B40549B0296065B2300330592569A7
B76B92BA1293585B6A9B604567A0901362856373B4B56897946256B4172B1B50474351364749A33996A81BA8847347A8
411B850B79A03018291672AA0945656A159AA6AA0A845531A592005B8A34366B882257107B190969A846474836A98007
50778920BA797297A2791101B0685A86BB704B9BAA17B055293679843B35215B0A8B1182B611953B080AA5431B219907
A8448A81B1A9493245676B88013B470335240859594158621014216619553246570601967448B470174B924489244481
7453865A4003B5AA7176451AAB90681A949786154AA040477382BA69371041710B8728458A23979252B254236753A44A
1900AA283536A227648812525743868B410A567794663359A6726A5286783328135114789B7645505B047848020A730A
9557B206776AA56A19682744107901306B29008808619866B4911A05264B872A46B5376383932699531B449195640B62
A63622830886247A47B3957169861239358041AA281333622AA15912B0A636047A489BB0726282A78B96671B27305A96
52496B9B999011A7BA36898891665B1A6009058978850A21B01A158A1473B84A192B8672542A2A7056581995207A436A
5B3BA2824637A3112ABB57176468206A071200A327B3216425148100786502AA21236ABB35499277670A126973058340
3B1922A483856007301983989159BB688A58B602339806B63002A339A50B0BA533B84827793913081070A32595A10180
3A9A20234691B1A0B623274B69B0B44688195169461059543A252BB05208720BA13118266A872B26B9B584959B451795
19534B221A335A2BB6971B3276B3A63A5B791723109B176529BB90651584279B7825712521B8269800738B07A62B1454
7884414451224092937165625696557A78799A82126613535A36B410309B759976119777B895801074B9779B9B513753
8B2799951012273399BB818B721967957713B90947B2A11A6A665848B22B531726616515939323229080B8AB574AA749
4773AB411A57150203067A112944833235A86153803A98689A0762B79835413A46B347888A4AAB259665694B93129B62
1391751430A98B002620718437A7B85B891179479651AA3410663715415B55BA47AA59465AB81567B7655780A8038135
85230122578485B071A529692B19A6537B28616A63556816945380634A90470354AAB303884B7B09B2037B95405BA145
704B19B14AA8028810881AB6072441194A875477836B37704B5199062319A336375437403562A663B835B891957883AB

Hint: Lambert Meertens. Tweak the algorithm you find ;-)

Regards,
Bengt Richter