Program that can find a find a file for you ?

[Thomas Guettler]

Am Wed, 29 Sep 2004 11:25:39 +0200 schrieb Peter Hansen:

> Greetings.
> 
> Im trying to write a program that can be run from the command line.
> If I want to search for example after a file with the ending .pdf, I should 
> be able to write in the command line:
> python  name of my program / the libary to search and what kind of file it 
> is example a .pdf file
> So if my program name was test.py and the library name was library1 and the 
> test type i wanted to find was, a .pdf file
> I should write python test.py /library1 .pdf

Hi,

This is something the "find" command does in a unix environment.

Here is my solution:

You could use this:
find.py your_path 'library1.*\.pdf$'

#!/usr/bin/env python
# -*- coding: iso-8859-1 -*-


# Python Imports
import os
import re
import sys

def usage():
    print """Usage: %s path regex
Print all files or directories with match the regex.

See this URL for the syntax of the regular expressions
http://docs.python.org/lib/re-syntax.html

    """ % (os.path.basename(sys.argv[0]))

def visit(regex, dirname, names):
    for name in names:
        p=os.path.join(dirname, name)
        if regex.search(p):
            print p
def main():
    if len(sys.argv)!=3:
        usage()
        sys.exit(1)
    path=sys.argv[1]
    regex=sys.argv[2]
    os.chdir(path)
    regex=re.compile(regex)
    os.path.walk(".", visit, regex)
    
if __name__=="__main__":
    main()