\number parameter in regular expression
Michael Hoffman
m.h.3.9.1.without.dots.at.cam.ac.uk at example.com
Sat Sep 25 09:31:52 EDT 2004
Piet wrote:
> import re
> pattern = re.compile("([a-zA-Z]*)(.*)(\d{4}-\d{2}-\d{2})\1")
You should be using a raw string, r"([a-z...". As a purely stylistic
concern, I found that calling this regex object "pattern" somewhat
confusing since that is normally what one calls the string that is
compiled into a regex.
regex = re.compile(r"([a-zA-Z]*)(.*)(\d{4}-\d{2}-\d{2})\1")
^
>>> regex.search("Date#ThisIsASpacer2004-09-25Date").groups()
('Date', '#ThisIsASpacer', '2004-09-25')
--
Michael Hoffman
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