Sorting a dictionary field belonging to a list

[John Lenton]

On Fri, Sep 17, 2004 at 02:51:22PM -0400, Jocknerd wrote:
> I have a list called teamlist which contain dictionaries of teams.  These
> are the fields in my team dictionary:
> 
> name, won, lost, tied, pf, pa
> 
> To print standings I do the following:
> 
> def printStandings(teamlist):
>    for team in teamlist:
>       print (team['name'], team['won'], team['lost'], team['tied'],
>       team['pf'], team['pa'])
> 
> My question is how would I go about sorting the output based on team['pf']
> for instance?

replace

    for team in teamlist:

using the decorate-sort-undecorate pattern,

    sortedlist = [(i['pf'], i) for i in teamlist]
    sortedlist.sort()
    for pf, team in sortedlist:

(this is far faster than calling a python function on each comparison);
in 2.4 you will be able to do

    for team in sorted(teamlist, operator.itemgetter('pf')):

-- 
John Lenton (john at grulic.org.ar) -- Random fortune:
Do not drink coffee in early A.M.  It will keep you awake until noon.
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