Enumerate question: Inner looping like in Perl

[Bengt Richter]

On Sun, 31 Oct 2004 12:28:47 +0200, Pekka Niiranen <pekka.niiranen at wlanmail.com> wrote:

>Steven Bethard wrote:
>> Pekka Niiranen <pekka.niiranen <at> wlanmail.com> writes:
>> 
>> 
>>>for i, row in enumerate(contents):
>>>	row[i] = something
>>>	if matcherSTART.search(row):
>>>		"Oops! how to advance 'i' and 'row' untill:
>>>		if matcherEND.search(row):
>>>			continue
>> 
>> 
>> Usually I would do this kind of thing by just keeping the iterator around.  The
>> example below has two loops, an outer and an inner, and both iterate over the
>> same enumeration.  (I've used 'char ==' instead of regular expressions to make
>> the output a little clearer, but hopefully you can do the translation back to
>> regexps for your code.)
>> 
>> 
>>>>>contents = list('abcdefg')
>>>>>itr = enumerate(contents)
>>>>>for i, char in itr:
>> 
>> ... 	print 'outer', i, char
>> ... 	contents[i] = char.upper()
>> ... 	if char == 'd':
>> ... 		for i, char in itr:
>> ... 			print 'inner', i, char
>> ... 			if char == 'f':
>> ... 				break
>> ... 			
>Thanks, I decided to catch logical error of not
>finding "f" -letter at all with:
>
> >>> def myiter(contents):
>... 	itr = enumerate(contents)
>... 	for i, char in itr:
>... 		print 'outer', i, char
>... 		if char == 'd':
#XXX# >... 			#try:
>... 				for i, char in itr:
>... 					print 'inner', i, char
>... 					if char == 'f':
>... 						break
                                else:
                                    print "f not found"
#XXX >... 			#except StopIteration:
#XXX >... 			#	print "f not found"
>...
> >>> contents = list('abcdeg') 				
> >>> myiter(contents)
>outer 0 a
>outer 1 b
>outer 2 c
>outer 3 d
>inner 4 e
>inner 5 g
>
>Not working: Iter() takes care of its own exceptions?
>This recurring feeling that writing REALLY correct programs in Python
>is not easier than in lower level languages... :(
>
>-pekka-
>
>
>
>
>
>> outer 0 a
>> outer 1 b
>> outer 2 c
>> outer 3 d
>> inner 4 e
>> inner 5 f
>> outer 6 g
>> 
>>>>>contents
>> 
>> ['A', 'B', 'C', 'D', 'e', 'f', 'G']
>> 
>> Steve
>> 
Try above (untested), noting:
 >>> itr = enumerate('abcdef')
 >>> for i,c in itr:
 ...     print i,c
 ...     if c=='d': break
 ... else:
 ...     print 'first else'
 ...
 0 a
 1 b
 2 c
 3 d
 >>> for i,c in itr:
 ...     print i,c
 ...     if c=='z': break
 ... else:
 ...     print '2nd else'
 ...
 4 e
 5 f
 2nd else

Regards,
Bengt Richter