Function name inside function (was RE: End of file)

[Robert Brewer]

Andrew Durdin wrote:
> Another [sort-of related] question: why does the following not produce
> a NameError for "foo"?
> 
> def foo(): print foo
> foo()

At what point did you expect the NameError?

>>> def foo(): print foo
... 
>>> import dis
>>> dis.dis(foo)
  1           0 LOAD_GLOBAL              0 (foo)
              3 PRINT_ITEM          
              4 PRINT_NEWLINE       
              5 LOAD_CONST               0 (None)
              8 RETURN_VALUE        


The inner 'foo' isn't looked up until the function is called, at which
time, 'foo' is present in globals().


Robert Brewer
MIS
Amor Ministries
fumanchu at amor.org