append to items depending on prior item

[Peter Otten]

M. Clift wrote:

> Now I know that the code is hopelessly wrong

[...]

> Could someone show me a short way

>>> items = "item1 item4 item2 item1".split()
>>> [i + random.choice(dict(item1="abc", item2="def").get(p, [""])) for (p,
i) in zip(items[-1:]+items[:-1], items)]
['item1c', 'item4c', 'item2', 'item1f']


Peter