convert scientific integer to normal integer

[Paul McGuire]

"les ander" <les_ander at yahoo.com> wrote in message
news:a2972632.0410050751.6b0b39d at posting.google.com...
> Hi,
> i have a file with lines like this:
>   1.7000000e+01   2.4000000e+01   1.0000000e+00   8.0000000e+00
1.5000000e+01
>   2.3000000e+01   5.0000000e+00   7.0000000e+00   1.4000000e+01
1.6000000e+01
>   4.0000000e+00   6.0000000e+00   1.3000000e+01   2.0000000e+01
2.2000000e+01
>   1.0000000e+01   1.2000000e+01   1.9000000e+01   2.1000000e+01
3.0000000e+00
>   1.1000000e+01   1.8000000e+01   2.5000000e+01   2.0000000e+00
9.0000000e+00
>
> Notice that they are all integers.
> What I want to do is write them out in a regular way, by which I mean that
the
> output should look like this:
> 17 24 1 9 15
> 23 5 7 14 16
> etc
>
> I tried the following but it did not work:
> fp=open(argv[1])
> for x in fp:
>   xc=[int(e) for e in x.split()]
>   print " ".join(xc)
>
>
> any help would be much appreciated
int(e) fails because it doesn't like the decimal point.  See below, using
int(float(e)).

-- Paul

---------------------------------
testdata = """
1.7000000e+01   2.4000000e+01   1.0000000e+00   8.0000000e+00
1.5000000e+01
2.3000000e+01   5.0000000e+00   7.0000000e+00   1.4000000e+01
1.6000000e+01
4.0000000e+00   6.0000000e+00   1.3000000e+01   2.0000000e+01
2.2000000e+01
1.0000000e+01   1.2000000e+01   1.9000000e+01   2.1000000e+01
3.0000000e+00
1.1000000e+01   1.8000000e+01   2.5000000e+01   2.0000000e+00
9.0000000e+00
"""

for line in testdata.split('\n'):
    print [ int(float(e)) for e in line.split() ]
---------------------------------
gives:
[]
[17, 24, 1, 8, 15]
[23, 5, 7, 14, 16]
[4, 6, 13, 20, 22]
[10, 12, 19, 21, 3]
[11, 18, 25, 2, 9]
[]