newbie: why it does not work: command=sys.exit?

[Kirk Strauser]

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At 2004-05-23T22:54:53Z, "Paul van Dam" <paul.van.dam at planet.nl> writes:
> import sys
> widget = Button(None, text='Hello widget world', command = sys.exit)


> Traceback (most recent call last):
>   File "I:\Python\Projecten\#Prog_in_Python\Hfst06\gui02.py", line 5,
> in -toplevel-
>     widget.mainloop()
>   File "D:\Python23\lib\lib-tk\Tkinter.py", line 965, in mainloop
>     self.tk.mainloop(n)
>   File "D:\Python23\lib\lib-tk\Tkinter.py", line 1347, in __call__
>     raise SystemExit, msg
> SystemExit

- From "pydoc sys.exit"

    Help on built-in function exit in sys:

    sys.exit = exit(...)
        exit([status])

        Exit the interpreter by raising SystemExit(status).  If the status
        is omitted or None, it defaults to zero (i.e., success).  If the
        status is numeric, it will be used as the system exit status.  If it
        is another kind of object, it will be printed and the system exit
        status will be one (i.e., failure).

The documentation says that calling sys.exit raises a SystemExit exception.
Your program calls sys.exit and gets a SystemExit exception.  It seems to be
working as expected and documented, unless I'm missing something.
- -- 
Kirk Strauser
The Strauser Group
Open. Solutions. Simple.
http://www.strausergroup.com/
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