introspection: How to find out the class defining a method

[Jeremy Yallop]

Holger Joukl wrote:
> Python 2.1 (#3, Jun  1 2001, 15:51:25)
> [GCC 2.95.2 19991024 (release)] on sunos5
> Type "copyright", "credits" or "license" for more information.
>>>> class Foo:
> ...     def do(self):
> ...             pass
> ...
>>>> class Moo(Foo):
> ...     pass
> ...
>>>> x=Moo()
>>>> x.do.im_class
><class __main__.Foo at cd7b4>
>>>>
> 
> Is there an elegant way to achieve the latter result (i.e. the base
> class in which this method actually is defined) in python 2.3, too?
> Couldn´t find it in the docs.

I'm not sure this qualifies as "elegant".  I think it gives the right
answer when it works, though.

  def class_defining_method(method):
     for c in inspect.getmro(method.im_class):
             if c.__dict__.has_key(method.im_func.__name__):
                     return c

Jeremy.