Passing parameters using **kargs
Aahz
aahz at pythoncraft.com
Tue Jun 8 14:28:26 EDT 2004
In article <mailman.699.1086698522.6949.python-list at python.org>,
Terry Reedy <tjreedy at udel.edu> wrote:
>
>Or if you don't care, or want to intercept invalid calls. Interestingly,
>the OP's example is the beginning of a possible debug wrapper usage where
>one either does not have a function's code or does not want to modify it
>directly. Possible example:
>
>_f_orig = f
>def f(*largs, **kargs):
> print 'f called with' largs, 'and', kargs
> f(*largs, **kargs)
You mean
_f_orig(*largs, **kargs)
I prefer this version:
def debugParams(func):
def debugger(*args, **kwargs):
for arg in args:
print type(arg), arg
for name in kwargs:
value = kwargs[name]
print name, type(value), value
return func(*args, **kwargs)
return debugger
f = debugParams(f)
--
Aahz (aahz at pythoncraft.com) <*> http://www.pythoncraft.com/
"as long as we like the same operating system, things are cool." --piranha
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