Passing parameters using **kargs

[Terry Reedy]

"Duncan Booth"
> Thomas Philips) >
> > I want to access parameters that are passed into a function using the
> > **kargs idiom. I define f(**kargs) via
> >
> > def f(**kargs):
> >     print kargs

> The ** argument is for keyword arguments where you don't know in advance
> all the keywords that might be valid.

Or if you don't care, or want to intercept invalid calls.  Interestingly,
the OP's example is the beginning of a possible debug wrapper usage where
one either does not have a function's code or does not want to modify it
directly.  Possible example:

_f_orig = f
def f(*largs, **kargs):
  print 'f called with' largs, 'and', kargs
  f(*largs, **kargs)

Terry J. Reedy