Misunderstanding about closures

[Alexander Schmolck]

"Michael Geary" <Mike at DeleteThis.Geary.com> writes:
> g = []
> def outer():
>     x = 1
>     def f():
>         return x
>     g.append( f )
>     x = 2
>     g.append( f )
>
> outer()
> print g[0](), g[1]()
>
> This prints:
>
> 2 2

> Now I am guessing that if you translated this code into any language that
> supports closures, including Scheme, you would get the "2 2" result, is that
> right?

Yep -- here's the scheme version.

(define g '())
(define (outer)
    (let* ((x 1)
           (f (lambda () x)))
      (set! g (cons f g))
      (set! x 2)
      (set! g (cons f g))))
(outer)
(list ((car g)) ((cadr g)))
=> (2 2)

'as