Howegrown wordcount

[Grégoire Dooms]

Larry Bates wrote:
> Something like this?
> 
> def wordcount(input, sep=" "):
>     global words
>     if isinstance(input, str):
>         words+=len([x.strip() for x in input.split(sep)])

What's the purpose of stripping the items in the list if you just count 
their number ? Isn't this equivalent to
           words += len(input.split(sep))

>         return words
>     else:
>         for item in input:
>             wordcount(item)
> 
>     return words

Removing the global statement and sep param, you get:

def wordcount(input):
     if isinstance(input, str):
         return len(input.split())
     else:
         return sum([wordcount(item) for item in input])

--
Grégoire Dooms