Hi Robert,
Robert Oschler wrote:
> l = re.split("[.?!]", x)
> I want to keep the punctuation marks.
The docs say: If _capturing parentheses_ are used in pattern, then the text
of all groups in the pattern are also returned as part of the resulting
list.
So:
l = re.split("([.?!])", x)
will work as wanted.
Bye,
Kai