Numeric - Multiply a byte array by a float.
Christopher T King
squirrel at WPI.EDU
Wed Jul 14 09:57:58 EDT 2004
On 13 Jul 2004, Kamilche wrote:
> I have a need to multiply all the bytes in a Numeric array, by a
> float, such as .9, .8, etc. I can't figure out a way to do that.
By "all the bytes in a Numeric array", I'm assuming you mean you have an
Int8 or UInt8 array. Correct me if I'm wrong.
> Does anyone have a clue how this is accomplished? I need the resulting
> array to be truncated to an array of bytes.
This should work, assuming my above assumption is correct:
byte_array = array([1,2,3,4,5,6],Int8)
byte_array = (byte_array*.5).astype(Int8)
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