Regular expression returning an index where match was found?

[Robert Brewer]

Jon Nicoll wrote:
>     myfunc("abc", "abcdefabcabc")
> 
> would return (say) a list [0, 6, 9]
> 
> I can't see a straightforward way of doing this from reading the
> Regular Expression HOWTO and the python docs; any
> pointers/suggestions?

Use finditer (which returns match objects), then match.start.


Robert Brewer
MIS
Amor Ministries
fumanchu at amor.org