iterator over a numarray?

[Colin J. Williams]

Alex Hunsley wrote:

> I'm looking for a way to iterate over all the items in a numarray.
> Writing a few nested loops isn't going to cut it, because the numarray 
> in question could be of any dimension...
> I am aware of the revel function, but that appears to just flatten the 
> numarray. What I need is an iterator that can give each value and the 
> coordinates in the array of that item....
>
> thanks
> alex

Alex,

You might try something like:
import numarray as _num
a= _num.arange(48, shape= (4, 4, 3))
b=  iter()
c= b.next()
print `c`
d= b.next()
print `d`
This gives:
array([[ 0,  1,  2],
       [ 3,  4,  5],
       [ 6,  7,  8],
       [ 9, 10, 11]])
array([[12, 13, 14],
       [15, 16, 17],
       [18, 19, 20],
       [21, 22, 23]])
You can see that we move along the first dimension.

ravel() flattens an array in situ, flat delivers a flattened array.

Colin W.