help with this game

[Greg Krohn]

Alex Endl wrote:
> ok now that i know the random function, i made this guessing game.  I get an
> error though, and Im new so im not to good at figuring out what its talking
> about.

When you need help figuring out an error, be sure to post your exception 
traceback.
This is the one I got when I ran your code:

Traceback (most recent call last):
   File "...\pywin\framework\scriptutils.py", line 310, in RunScript
     exec codeObject in __main__.__dict__
   File "...\greg\My Documents\Projects\Script1.py", line 15, in ?
     print "trie number", c ("out of 10")
TypeError: 'int' object is not callable

Now, on to your code:

> import random
> a = random.randint(1, 100)
> b=-100
> c=0
> print "Welcome to guess the number"
> print "to play type in a number between 1 and 100."
> print "but you only get ten tries"
> while a != b:
>     c = c + 1
>     b = input ("enter guess:")
>     if b < a :
>         print "to low"
>         if c == 10:
>             print "to many guesses"
>         print "trie number", c ("out of 10")

The problem is on this line (and line 20 also, of course). What you most 
likely want is:

 >         print "trie number", c, "(out of 10)"

Note that I added a comma and moved the quotation marks. The syntax 
foo(bar) is for calling function named foo with an argument called bar. 
Just like randint and input. So Python thought c was your function and 
"out of 10" was an argument. But, alas, c in an int, not a function, so 
it couldn't call it. That's the error.

>     elif b > a :
>         print ("to high")
>         if c == 10:
>             print "to many guesses"
>         print "trie number", c ("out of 10")
> print "you got it in ",c," tries"
> 
> 
> thanks for your time

No problem, my time is worthless. ;)

greg