Escaping slashes (double backslash plague)

[anton muhin]

Aloysio Figueiredo wrote:
> I need to replace every ocurrence of '/' in s by '\/'
> in order to create a file named s. My first attempt
> was:
> 
> s = '\/'.join(s.split('/'))
> 
> but it doesn't work:
> 
> 
>>>>s = 'a/b'
>>>>s = '\/'.join(s.split('/'))
why not replace: s.replace('\/', '/')?

>>>>s
> 
> 'a\\/b'
> 
>>>>repr(s)
> 
> "'a\\\\/b'"
Try print s, and you'll see what you want.
> 
> 
> '\/'.join() escapes the backslashes and I don't know
> why. 
> 
> Any help?
> 
> Aloysio Figueiredo
> 
regards,
anton.