NEWLINE character problem

[Dragos Chirila]

Thanks a LOT !!

I will give it a try and see how it works... the problem is that I have
realy big strings (more than 50000 characters)

Dragos

----- Original Message ----- 
From: "Tim Peters" <tim.one at comcast.net>
To: <python-list at python.org>
Sent: Friday, January 30, 2004 5:49 PM
Subject: RE: NEWLINE character problem


> [Nuff, replying to someone who has strings with various line-end
>  conventions]
>
> > Say your string is s; then you could use the following
> > function (untested!) to make sure that s uses \n only:
> >
> >     def fix_lineendings(txt):
> >         if txt.count('\r\n'):  # MS DOS
> >             txt = txt.replace('\r\n', '\n')
> >         elif txt.count('\r'):  # Mac
> >             txt = txt.replace('\r', '\n')
> >
> >         return txt
> >
> > Simply write: s = fix_lineendings(s)
>
> That's in the right direction.  There's no need to count the *number* of
> each kind of oddball, and .count() does all the work that .replace() does
> anyway if there aren't any oddballs.  So the one-liner:
>
>     return s.replace('\r\n', '\n').replace('\r', '\n')
>
> does the same, but quicker.  Note that, as an internal optimization,
> .replace() doesn't build a new string object unless it finds something to
> replace, so it's actually slower to do an "if" test first.
>
> >>> s = 'abcdefghi\n\n'  # doesn't contain any oddballs
> >>> t = s.replace('\r\n', '\n').replace('\r', '\n')
> >>> s == t
> True  # nothing was replaced
> >>> s is t
> True  # more, the same string object was returned by both .replace()s
> >>>
>
>
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