hmm, lets call it: generic init problem ['LBBW': checked]

[Michele Simionato]

"Holger Joukl" <Holger.Joukl at LBBW.de> wrote in message news:<mailman.70.1077206479.27104.python-list at python.org>...
> I just started out with python 2.3, so I might be totally wrong,
> but does this work?
> 
> >>> class one(object):
> ...     def   init  (self, *args, **kwargs):
> ...             super(self.  class  , self).  init  ()
> ...
> >>> one()
> <  main  .one object at 0x1dd190>

This is tempting, but breaks under inheritance:
    
class A(object):
    def __init__ (self):
        print "A.__init__"
        super(self.__class__, self).__init__()
class B(A):
    def __init__ (self):
        print "B.__init__"
        super(self.__class__, self).__init__()

b=B()

Here B.__init__ will call A.__init__ which will call itself, generating
an infinite loop. The reason is that in A.__init__, when self=b, one
has super(self.__class__,self).__init__() == super(B,b).__init__()
which will call A.__init__(b) again and again.

       Michele Simionato