split a string and build tuple

[Jonathan Daugherty]

# having a string space separated like : s = "w1 w2 w3 w4 w5 w6 w7 w8..."
# how to get : l = (('w1', 'w2', 'w3'), ('w4', 'w5', 'w6'), ('w7', 'w8', ...),
# ...) ?
# (a kind of splitting and grouping in an elegant way)

>>> import string
>>> s = "w1 w2 w3 w4 w5 w6 w7 w8"
>>> x = string.split(s) 
>>> x
['w1', 'w2', 'w3', 'w4', 'w5', 'w6', 'w7', 'w8']
>>> for index in range(0, len(x), 3):
...     print x[index:index + 3]
... 
['w1', 'w2', 'w3']
['w4', 'w5', 'w6']
['w7', 'w8']

-- 

  Jonathan Daugherty
  http://www.cprogrammer.org

  "It's a book about a Spanish guy called Manual, you should read it."
                                                            -- Dilbert