create lowercase strings in lists - was: (No subject)
Mark Devine
markdevine at eircom.net
Fri Dec 17 05:31:14 EST 2004
If I use:
if el.issubset(testelement):
I get a closer anwser but the brackets cause a problem. They are optional in the test list so (D) in the test list is equal to D or (D) in the reference list.
"Mark Devine" <markdevine at eircom.net> wrote:
>
> I got the script working. Thanks for all your help everyone. Trouble is its not showing the correct results. Here is the script and results:
>
> #!/usr/bin/env python
> import os
> import sys
> import time
> import string
> import pexpect
> import commands
> from sets import Set as set
>
>
> # Test if the words of list2 elements appear in any order in list1 elements
> # disregarding case and parens
>
> # Reference list
> list1 = ["a b C (D)", "D A B", "A B E"]
> # Test list
> list2 = ["A B C D", "A B D", "A E F", "A (E) B", "A B", "E A B" ]
>
> def normalize(text, unwanted = "()", table = string.maketrans(string.ascii_uppercase,string.ascii_lowercase)):
> text.translate(table,unwanted)
> return set(text.split())
>
> reflist = [normalize(element) for element in list1]
> print reflist
>
> #This is the list of sets to test against
>
>
> def testmember(element):
> """is element a member of the reflist, according to the above rules?"""
> testelement = normalize(element)
> #brute force comparison until match - depends on small reflist
> for el in reflist:
> if el.issuperset(testelement):
> return True
> return False
>
> for element in list2:
> print element, testmember(element)
>
> Here is the results:
>
> $ ./test.py
> [Set(['a', 'C', 'b', '(D)']), Set(['A', 'B', 'D']), Set(['A', 'B', 'E'])]
> A B C D False
> A B D True
> A E F False
> A (E) B False
> A B True
> E A B True
>
> The results should be:
>
> > A B C D True
> > A B D True
> > A E F False
> > A (E) B True
> > A B False
> > E A B True
>
>
>
>
>
> Michael Spencer <mahs at telcopartners.com> wrote:
>
> >
> > Steve Holden wrote:
> > > Mark Devine wrote:
> > >
> > >> Actually what I want is element 'class-map match-all cmap1' from list
> > >> 1 to match 'class-map cmap1 (match-all)' or 'class-map cmap1 mark
> > >> match-all done' in list 2 but not to match 'class-map cmap1'.
> > >> Each element in both lists have multiple words in them. If all the
> > >> words of any element of the first list appear in any order within any
> > >> element of the second list I want a match but if any of the words are
> > >> missing then there is no match. There are far more elements in list 2
> > >> than in list 1.
> > >>
> > >
> > sounds like a case for sets...
> >
> > >>> # NB Python 2.4
> > ...
> > >>> # Test if the words of list2 elements appear in any order in list1 elements
> > >>> # disregarding case and parens
> > ...
> > >>> # Reference list
> > >>> list1 = ["a b C (D)",
> > ... "D A B",
> > ... "A B E"]
> > >>> # Test list
> > >>> list2 = ["A B C D", #True
> > ... "A B D", #True
> > ... "A E F", #False
> > ... "A (E) B", #True
> > ... "A B", #True
> > ... "E A B" ]
> > ...
> > >>> def normalize(text, unwanted = "()"):
> > ... conv = "".join(char.lower() for char in text if char not in unwanted)
> > ... return set(conv.split())
> > ...
> > >>> reflist = [normalize(element) for element in list1]
> > >>> print reflist
> > ...
> > [set(['a', 'c', 'b', 'd']), set(['a', 'b', 'd']), set(['a', 'b', 'e'])]
> >
> > This is the list of sets to test against
> >
> >
> > >>> def testmember(element):
> > ... """is element a member of the reflist, according to the above rules?"""
> > ... testelement = normalize(element)
> > ... #brute force comparison until match - depends on small reflist
> > ... for el in reflist:
> > ... if el.issuperset(testelement):
> > ... return True
> > ... return False
> > ...
> > >>> for element in list2:
> > ... print element, testmember(element)
> > ...
> > A B C D True
> > A B D True
> > A E F False
> > A (E) B True
> > A B True
> > E A B True
> > >>>
> >
> > Michael
> >
> > --
> > http://mail.python.org/mailman/listinfo/python-list
> >
>
>
>
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