Python xmlrpc servers?

[ted holden]

Skip Montanaro wrote:


>     ted> I don't see what "lambda" is or how a lambda function is supposed
>     ted> to be construed as adding two numbers together.
> 
> Lambda is a keyword in Python used to create and return very simple
> (single-expression) functions.  Lambda expressions can be used anywhere
> you'd normally use a function object.  See:
> 
>     http://www.python.org/doc/current/ref/lambdas.html
> 
> The line containing the lambda expression:
> 
>     server.register_function(lambda x,y: x+y, 'add')
> 
> could be recast as:
> 
>     def add(x, y):
>         return x+y
> 
>     server.register_function(add, 'add')

That's a whole lot easier to digest.  I'd have assumed lambda was some sort
of stat function...


> The server listens to "localhost" on port 8888.  To allow it to listen for
> external connections change "localhost" to the name or IP address of the
> server.  Before you do that make sure you understand the ramifications of
> exposing your XML-RPC server to a broader class of potential clients, some
> of which are bound to be malicious.
> 
> Skip


Many thanks, that's the part I was missing in the case of standalone
servers.  The only other real question is what about the cgi servers?  I'd
assume I'd take the example given:

class MyFuncs:
    def div(self, x, y) : return div(x,y)

handler = CGIXMLRPCRequestHandler()
handler.register_function(pow)
handler.register_function(lambda x,y: x+y, 'add')
handler.register_introspection_functions()
handler.register_instance(MyFuncs())
handler.handle_request()

Stuff that into a file in the cgi-bin dir on the server, and then try to use
something like: 


server = xmlrpclib.Server("http://192.168.1.102/testserver.py")
or
server = xmlrpclib.Server("http://192.168.1.102/cgi-bin/testserver.py")


That still hasn't worked, so far at least.