Regular Expression

[Binu K S]

You can do this without regular expressions if you like

>>> uptime='12:12:05  up 21 days, 16:31, 10 users,  load average:
0.01, 0.02, 0.04'
>>> load = uptime[uptime.find('load average:'):]
>>> load
'load average: 0.01, 0.02, 0.04'
>>> load = load.split(':')
>>> load
['load average', ' 0.01, 0.02, 0.04']
>>> load[1].split(',')
[' 0.01', ' 0.02', ' 0.04']

One liner:
>>> uptime[uptime.find('load average:'):].split(':')[1].split(',')[0]
' 0.01'

On Tue, 14 Dec 2004 23:16:43 -0700, Michael McGarry
<replytogroup at nospam.org> wrote:
> Hi,
> 
> I am horrible with Regular Expressions, can anyone recommend a book on it?
> 
> Also I am trying to parse the following string to extract the number
> after load average.
> 
> ".... load average: 0.04, 0.02, 0.01"
> 
> how can I extract this number with RE or otherwise?
> 
> Michael
> --
> http://mail.python.org/mailman/listinfo/python-list
>