type method-wrapper?

[Alan Kennedy]

Thomas Guettler wrote:
> Hi,
> l=[]
> print type(l.__delattr__)
> # --> <type 'method-wrapper'>
> 
> I didn't find a corresponding type in the modules "types".
> Is it missing or am I blind?
> 
> (Python 2.3.3)

I don't have the answer to the question, but perhaps this sheds a little 
more light on it?

Python 2.3.4 (#53, May 25 2004, 21:17:02) [MSC v.1200 32 bit (Intel)] on 
win32
Type "help", "copyright", "credits" or "license" for more information.
 >>> l = []
 >>> type(l.__delattr__)
<type 'method-wrapper'>
 >>> import types
 >>> for t in dir(types):
...  if t[-4:] == 'Type' and isinstance(l.__delattr__, getattr(types, t)):
...   print "It's a '%s'" % str(t)
...
It's a 'ObjectType'
 >>>

I also am interested in what <type method-wrapper> is.

regards,

-- 
alan kennedy
------------------------------------------------------
email alan:              http://xhaus.com/contact/alan