Lazy argument evaluation (was Re: expression form of one-to-many dict?)

[Nick Coghlan]

Nick Coghlan wrote:
> def lazycall(x, *args, **kwds):
>   """Executes x(*args, **kwds)() when called"""
>   return lambda : x(*args, **kwds)()

It occurred to me that this should be:

def lazycall(x, *args, **kwds):
    """Executes x()(*args, **kwds) when called"""
    return lambda : x()(*args, **kwds)

(Notice where the empty parens are)

Then this does the right thing:

lazycall(lazy(attrgetter('a'), x), y) # x.a(y)

Cheers,
Nick.

-- 
Nick Coghlan   |   ncoghlan at email.com   |   Brisbane, Australia
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