Regular Expressions

[Isaac To]

>>>>> "Jens" == Jens Thiede <jens.news at webgear.co.za> writes:

    Jens> What is the easiest way to generate a list that contains all
    Jens> the remnants of re.findall (the inverse of the following).

You mean, complement?

    Jens> re.split doesn't seem to work quite well

Why?

>>> obj=re.compile(r'<t>.*?</t>', re.S|re.I)
>>> obj.split('def<T>abc\n def</T>ghi jkl\nmno\n<t>abc</t>haha')
['def', 'ghi jkl\nmno\n', 'haha']
>>> obj.findall('def<T>abc\n def</T>ghi jkl\nmno\n<t>abc</t>haha')
['<T>abc\n def</T>', '<t>abc</t>']

>>> obj=re.compile(r'<t>.*</t>', re.S|re.I)
>>> obj.split('def<T>abc\n def</T>ghi jkl\nmno\n<t>abc</t>haha')
['def', 'haha']
>>> obj.findall('def<T>abc\n def</T>ghi jkl\nmno\n<t>abc</t>haha')
['<T>abc\n def</T>ghi jkl\nmno\n<t>abc</t>']

Looks like it is doing the job, right?

Regards,
Isaac.