How to clear previous console output?
Larry Bates
lbates at swamisoft.com
Mon Aug 2 17:10:24 EDT 2004
Try this class I use on both Linux and Windows
(console apps). See main program for example
usage.
HTH,
Larry Bates
class progressbarClass:
def __init__(self, finalcount, progresschar=None):
import sys
self.finalcount=finalcount
self.blockcount=0
#
# See if caller passed me a character to use on the
# progress bar (like "*"). If not use the block
# character that makes it look like a real progress
# bar.
#
if not progresschar: self.block=chr(178)
else: self.block=progresschar
#
# Get pointer to sys.stdout so I can use the write/flush
# methods to display the progress bar.
#
self.f=sys.stdout
#
# If the final count is zero, don't start the progress gauge
#
if not self.finalcount : return
self.f.write('\n------------------ %
Progress -------------------1\n')
self.f.write(' 1 2 3 4 5 6 7 8 9 0\n')
self.f.write('----0----0----0----0----0----0----0----0----0----0\n')
return
def progress(self, count):
#
# Make sure I don't try to go off the end (e.g. >100%)
#
count=min(count, self.finalcount)
#
# If finalcount is zero, I'm done
#
if self.finalcount:
percentcomplete=int(round(100*count/self.finalcount))
if percentcomplete < 1: percentcomplete=1
else:
percentcomplete=100
#print "percentcomplete=",percentcomplete
blockcount=int(percentcomplete/2)
#print "blockcount=",blockcount
if blockcount > self.blockcount:
for i in range(self.blockcount,blockcount):
self.f.write(self.block)
self.f.flush()
if percentcomplete == 100: self.f.write("\n")
self.blockcount=blockcount
return
if __name__ == "__main__":
from time import sleep
pb=progressbarClass(8,"*")
count=0
while count<9:
count+=1
pb.progress(count)
sleep(0.2)
pb=progressbarClass(100)
pb.progress(20)
sleep(0.2)
pb.progress(47)
sleep(0.2)
pb.progress(90)
sleep(0.2)
pb.progress(100)
print "testing 1:"
pb=progressbarClass(1)
pb.progress(1)
"Newgene" <newgene at bigfoot.com> wrote in message
news:cem5jm$pcs at odbk17.prod.google.com...
> Hi, group,
> May I ask a newbie question?
>
> Given the below example:
>
> for i in range(100):
> print "%s%%" % i
>
> I want to show the progress by print 1% to 100%. But I hope each
> output will clear the previous output before print, so that I can see a
> dynamic updated display of percentage, instead of print all percentages
> one by one. How can I do that(what about on both windows and unix
> platform)?
>
> Thank you in advance for your expertise.
>
> Best,
>
> Cl
>
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