minor bug in cmath.asin?

[Erik Max Francis]

Edwin Young wrote:

> I think it should be 0+0j (+0 for both parts). The official formula is
> at
> 
> http://functions.wolfram.com/ElementaryFunctions/ArcSin/02/

Well this is Mathematica's official formula ... :-).

> and is asin(z) = -i * log(i*z + sqrt(1 - z*z))
> 
> Which is slightly ambiguous. I read it as:
> 
> (+0 - 1i) * log(i*z + sqrt(1 - z*z))

How is the original equation amiguous?

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