Python 2.3.3 super() behaviour

[Josef Meile]

Peter Otten wrote:
 > As soon as a test() method without the super(...).test() is reached, no
 > further test methods will be invoked. Only the first in the list of base
 > classes will be invoked. If I'm getting it right you have to do something
 > like:
 >
 > class Base(object):
 >     def test(self):
 >         print "base"
 >
 > class D1(Base):
 >     def test(self):
 >         super(D1, self).test()
 >         print "derived 1"
 >
 > class D2(Base):
 >     def test(self):
 >         super(D2, self).test()
 >         print "derived 2"
 >
 > class All(D1, D2):
 >     pass
 >
 > All().test()
Ok, this produces almost what the original poster wanted. You
just have to invert the order of the base classes in All:

 >>>class All(D2, D1):
...   pass
...

then you will get:
 >>> All().test()
base
derived 1
derived 2

However, I don't understand jet why this doesn't print:

base
derived 1
base
derived 2

The method test of Base is called just once? Why?
I taught it was something like:

All.test() -> D1.test() + D2.test()

which is the same as:

(Base.test() + print "derived 1") + (Base.test() + print derived 2")

Thanks in advanced,
Josef