String + number split

[William Park]

Stevie_mac <no.email at please.com> wrote:
> Heres my solution...
> 
> import string
> def makefont(sFontName):
>     num = []
>     nam = []
>     acnt = 0
>     #reverse it
>     l = list(sFontName); l.reverse(); ''.join(l)
>     sFontName = string.join(l,'')
>      #now loop it while isdigit(), store number, then store alphas
>     for c in sFontName:
>         if c.isdigit() and acnt == 0:
>             num.append(c)
>         elif c.isalpha() or acnt > 1:
>             acnt += 1
>             nam.append(c)
>     nam.reverse()
>     num.reverse()
>     return (string.join( nam, '' ), int(string.join( num, '' )))
> 
> Now you see why i was asking for a more elegant solution!
> 
> PS, the number on the end may vary  &  the _ could be any non alpha char!
> 
>  font12        becomes         ('font',12)
>  arial_14      becomes        ('arial',14)
>  arial__8      becomes        ('arial',8)
>  times 6      becomes        ('times',6)

Assuming you only have 2 fields to worry about, play around with
    1. re.split('[^a-z0-9]+', '...')
    2. re.findall('[a-z]+|[0-9]+', '...')

Essentially, you want to pickout '[a-z]+' first and then '[0-9]+', ie.
    ([a-z]+)[^0-9]+([0-9]+)

-- 
William Park, Open Geometry Consulting, <opengeometry at yahoo.ca>
Linux solution/training/migration, Thin-client