How to assign a default constant value in a function declaration

[Vineet Jain]

Thanks for all the repsonses. It turns out that the following actually
works:

def someFunction(option=Constants.DEFAULT_VALUE):

I did want the evaluate "Constants.DEFAULT_VALUE" function definition time.
If that changes at function call time then it should not be in Constants.

So all in all it works as expected and I have changed all hard coded default
arguments in my functions to Constant.* values.

Thanks for all your help.


VJ

-----Original Message-----
From: python-list-bounces+vineet=eswap.com at python.org
[mailto:python-list-bounces+vineet=eswap.com at python.org]On Behalf Of
rzed
Sent: Monday, April 05, 2004 3:52 PM
To: python-list at python.org
Subject: Re: How to assign a default constant value in a function
declaration


Scott David Daniels <Scott.Daniels at Acm.Org> wrote in
news:4071a362 at nntp0.pdx.net:

> Marco Bartel wrote:
>
>> rzed wrote:
>>
[...]
>>> Do you mean in a context like this?
>>>    class Const:
>>>        someVal=255
>>>        otherVal=0
>>>
>>>    def blip(Const.someVal):
> Should be:
>        def blip(test=Const.someVal):
>>
>> i checked this out, and i think its the name you were using:
>> Const
> Nope, it is the missing arg name.
>

Well, not so much that as an incorrectly formed parameter name. I
can legally do this:
    	def blip( someVal ):
    	    	...

but not this:
    	def blip( x.someVal ):
=> SyntaxError aimed at the dot.

Since there is no argname to assign a value to, "Const.someVal" is
taken as an identifier for a passed-in parameter. But it seems
(sensibly enough) that an identifier can't contain a '.' character,
which evidently is reserved for a qualifier separator (or some such
term) in that context.

--
rzed

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