Datetime utility functions

[Christos TZOTZIOY Georgiou]

On Mon, 15 Sep 2003 20:44:08 +0100, rumours say that Paul Moore
<paul.moore at atosorigin.com> might have written:

[find the end of the month]

>The best solution I could find was
>
>def month_end(dt):
>    # Get the next month
>    y, m = dt.year, dt.month
>    if m == 12:
>        y += 1
>        m = 1
>    else:
>        m += 1
>
>    # Use replace to cater for both datetime and date types. This
>    # leaves the time component of a datetime unchanged - it's
>    # arguable whether this is the right thing.
>
>    return dt.replace(year=y, month=m, day=1) - datetime.timedelta(days=1)

I sent my own version without having seen your own --and mine might seem
obfuscated, compared to yours.  Only a minor suggestion: don't use
dt.replace, use dt.__class__ instead, since you wouldn't want your
function to have side-effects (that is, don't destroy the actual object
that dt is bound to.)
-- 
TZOTZIOY, I speak England very best,
Microsoft Security Alert: the Matrix began as open source.