unicode 3 digit decimal conversion

[Martin v. Löwis]

Rune Hansen <rune.hansen at viventus.no> writes:

> What I need is the converted string to read u'Gratis \248l' (*
> How do I do this without going through each and every character of the
> string?

You can register an error callback, like this:

import codecs

def decimal_escape(exc):
    try:
        data = exc.object
        res = u""
        for i in range(exc.start, exc.end):
            char = ord(data[i])
            if char < 1000:
                res += u"\\%03d" % char
            else:
                # Unsupported character
                raise exc

        return res, exc.end
    except:
        raise exc

codecs.register_error("decimal-escape", decimal_escape)

print u"Gratis \xf8l".encode("us-ascii", "decimal-escape")

Notice That your specification is a bit unclear as to what to do with
characters > 1000; I assume they are not supported in your protocol.

Regards,
Martin