Python syntax in Lisp and Scheme

[Christoph (news_chr)]

"Alex Martelli" wrote:
...
> def outer(a) proc do |b| a+=b end end
>
> x = outer(23)
> puts x.call(100)   # emits 123
> puts x.call(100)   # emits 223
>
> [i.e., I can't think of any way you could just use x(100)
> at the end of such a snippet in Ruby -- perhaps somebody
> more expert of Ruby than I am can confirm or correct...?]

Guy is probably thinking about something like this

---
def outer(sym,a)
  Object.instance_eval {
    private  # define a private method
    define_method(sym) {|b|  a+=b }
  }
end

outer(:x,24)

p x(100)   #   124
p x(100)   #   224
---


but there is no way to write a ``method returning
method ::outer in Ruby that could be used in the form

----
x = outer(24)
x(100)
----

On the other hand, using []-calling convention
and your original definition, you get - at least
visually - fairly close.

---
def outer(a) proc do |b| a+=b end end

x = outer(23)
puts x[100]   # emits 123
puts x[100]   # emits 223
---


/Christoph