Faster way to do this?

[Lulu of the Lotus-Eaters]

"John Wilson" <tug at wilson.co.uk> wrote previously:
|I think that there's a problem with the regexp.
|Looks like a single letter matches multiple times.

    pat = re.compile('(?im)^[%s]+$' % sys.argv[1].lower())

Hmmm...  I thought the original spec said "only the listed letters
occur".  I guess 'letter' is ambiguous between "type" and "token", I
thought of the first meaning.

Nonetheless, even assuming the latter meaning, using my regex can winnow
down the wordlist in 1/20th the time of the original approach.
Post-filtering the resulting 20 words should still be possible in less
than 19/20ths the time taken to filter all 50k dictionary words (all
numbers given only for general scale, not precise figures :-)).

Yours, Lulu...

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