Accessing nested functions for testing

[Gerrit Holl]

Chad Netzer schreef op dinsdag 20 mei om 20:40:33 +0000:
> Is there any way to access a nested function as though it were not
> nested (ie. for testing it directly)?
> 
> For example:
> 
> def foo():
>     def bar():
>         pass
>     bar()
> 
> Is it possible to execute bar from outside of foo?  I can't even find a
> way to see or access bar at all, from the global scope.
> 
> My intuition says this is not possible, I'm just curious if that is
> truly the case.

It is possible, but not Beatiful:

 81 >>> def foo():
 81 ...  def sub1():
 81 ...   def subsub1(): pass
 81 ...   def subsub2(): pass
 81 ...  def sub2(): pass
 81 ...  def sub3(): pass
 81 ...
 82 >>> foo.func_code.co_consts
(None, <code object sub1 at 0x400ce020, file "<stdin>", line 2>, <code object sub2 at 0x400ce060, file "<stdin>", line 5>, <code object sub3 at 0x400ce0a0, file "<stdin>", line 6>)
 85 >>> import types
 86 >>> [c for c in foo.func_code.co_consts if isinstance(c, types.CodeType)]
[<code object sub1 at 0x400ce020, file "<stdin>", line 2>, <code object sub2 at 0x400ce060, file "<stdin>", line 5>, <code object sub3 at 0x400ce0a0, file "<stdin>", line 6>]
 88 >>> [c for c in foo.func_code.co_consts if isinstance(c, types.CodeType)][0].co_name
'sub1'
 89 >>> [c for c in foo.func_code.co_consts if isinstance(c, types.CodeType)][1].co_name
'sub2'
 90 >>> [c for c in foo.func_code.co_consts if isinstance(c, types.CodeType)][1]
<code object sub2 at 0x400ce060, file "<stdin>", line 5>
 91 >>> exec [c for c in foo.func_code.co_consts if isinstance(c, types.CodeType)][1]

(executed)

yours,
Gerrit.

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